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Dimas [21]
3 years ago
13

What is -23/6 - 7/3A-37/6B-30/9C-16/6D37/6​

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

A

Step-by-step explanation:

i solved it

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One number is 6 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is580 ​,
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Step-by-step explanation:

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Zaid has a peculiar pair of four-sided dice. When he rolls the dice, the probability of any particular outcome is proportional t
Elden [556K]

Answer:   a) \bold{\dfrac{3}{16}}     b) \bold{\dfrac{1}{36}}

<u>Step-by-step explanation:</u>

a) In order to get an even number, you have the 3 different scenarios:

1) Even, Even, Even, Even     \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

2) Even, Even, Odd, Odd   \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

3) Odd, Odd, Odd, Odd   \dfrac{3\times 3\times 3\times 3}{6^4} \quad = \dfrac{3^4}{6^4}\quad =\dfrac{1}{16}

<em>Order doesn't matter</em>

Add them up to get your answer: \dfrac{1}{16}+\dfrac{1}{16}+\dfrac{1}{16}\quad =\large\boxed{\dfrac{3}{16}}

b) If one die is a 2 and another is a 3 and the other two dice can be any number, then you have 1 possibility for a 2, 1 possibility for a 3, and 6 possibilities for each of the other two dice.

\dfrac{1\times 1\times 6\times 6}{6^4}\quad =\dfrac{1}{6^2}\quad =\large\boxed{\dfrac{1}{36}}

3 0
3 years ago
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