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Dimas [21]
3 years ago
13

What is -23/6 - 7/3A-37/6B-30/9C-16/6D37/6​

Mathematics
1 answer:
8_murik_8 [283]3 years ago
7 0

Answer:

A

Step-by-step explanation:

i solved it

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Taylor is 2/3 as old as her cousin. the sum of their ages is 45. how old are taylor and her cousin
kiruha [24]
Her cousin is 27 and Taylor is 18 years old
7 0
3 years ago
(8m-3n)^2 - (4m+3n)^2​
natulia [17]

Answer:

48m^2-72mn

Step-by-step explanation:

We need to solve (8m-3n)^2 - (4m+3n)^2

We know that,

(a+b)^2=a^2+b^2+2ab\\\\(a-b)^2=a^2+b^2-2ab

Using the above formula,

(8m-3n)^2 - (4m+3n)^2=(8m)^2+(3n)^2-2(8m)(3n)-[(4m)^2+(3n)^2+2(4m)(3n)]\\\\=64m^2+9n^2-48mn-(16m^2+9n^2+24mn)\\\\=64m^2+9n^2-48mn-16m^2-9n^2-24mn\\\\=48m^2-48mn-24mn\\\\=48m^2-72mn

So, the final answer is 48m^2-72mn.

4 0
3 years ago
Please help!
Gemiola [76]

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

In this exercise we must apply the definition of derivative, which is described below:

f'(x) =  \lim_{x \to 0} a_n \frac{f(x+h)-f(x)}{h} (1)

If we know that f(x) = 2\cdot x^{2}-9, then the derivative of the expression is:

f'(x) =  \lim_{h \to 0} \frac{2\cdot (x+h)^{2}-9-2\cdot x^{2}+9}{h}

f'(x) = 2\cdot \lim_{h \to 0} \frac{x^{2}+2\cdot h\cdot x + h^{2}-2\cdot x^{2}}{h}

f'(x) = 2\cdot  \lim_{h \to 0} 2\cdot x + h

f'(x) = 4\cdot x

The derivative of f(x) = 2\cdot x^{2}-9 is f'(x) = 4\cdot x.

We kindly invite to check this question on derivatives: brainly.com/question/23847661

4 0
3 years ago
What is the amplitude of sin ?
sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

  • A = amplitude
  • b = period = 2π/b
  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

  • Amplitude = 2
  • b = 1 and therefore, period = 2π/1 = 2π
  • c = 0
  • d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

6 0
3 years ago
Explain the purposes of inductive and deductive reasoning in mathematics. Be sure to define both inductive reasoning and deducti
uysha [10]
When it comes to deductive reasoning, it is used to reach a logical solution. You start out with the general statement, or hypothesis, and examine all the possibilities so you can reach the final conclusion. 
Inductive reasoning is completely opposite - you focus on specific observations, and then make broad generalizations. 
7 0
4 years ago
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