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Amanda [17]
3 years ago
8

Steven and Gina each wrote an expression, but only Steven’s expression is equivalent to 4x - 8. What could be Gina’s expression?

Mathematics
1 answer:
Fed [463]3 years ago
4 0
2(2x-4) because when you multiply 2 x 2x it equals 4x. When you multiply 2 x 4 it equals 8. Leaving you with 4x-8
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Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs
Paladinen [302]

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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6 0
3 years ago
Please help 100 points ​
muminat

Answer:

Type that out please I can't read it sideways

Step-by-step explanation:

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