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3 years ago

13

Find the zeros of the function.

1 answer:

Verdich [7]3 years ago

7 0

Smaller x = -2/5

Larger x = 5

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A car is traveling down a highway at a constant speed, described by the equation d=65t , where d represents the distance, in mil

notsponge [240]

Answer: 97.5m

Step-by-step explanation:

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3 years ago

write the vertex form quadratic equation which has a vertex at (2,-1) and psses theough the point (4,3)

andrey2020 [161]

Answer:

Step-by-step explanation:

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3 years ago

Can someone please help me??

dmitriy555 [2]

Answer:

I is clear that, the linear equation $5x+12=5x-7$ has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

$\frac{2}{3}\left(9x+6\right)=6x+4$

$6x+4=6x+4$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$6x+4-4=6x+4-4$

$6x=6x$

$\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}$

$6x-6x=6x-6x$

$0=0$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

<u>Checking the 2nd option:</u>

$5x+12=5x-7$

$\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}$

$5x+12-5x=5x-7-5x$

$\mathrm{Simplify}$

$12=-7$

$\mathrm{The\:sides\:are\:not\:equal}$

$\mathrm{No\:Solution}$

<u>Checking the 3rd option:</u>

$4x+7=3x+7$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}$

$4x+7-7=3x+7-7$

$\mathrm{Simplify}$

$4x=3x$

$\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}$

$4x-3x=3x-3x$

$\mathrm{Simplify}$

$x=0$

<u>Checking the 4th option:</u>

$-3\left(2x-5\right)=15-6x$

$\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}$

$-6x+15-15=15-6x-15$

$\mathrm{Simplify}\$

$-6x=-6x$

$\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}$

$-6x+6x=-6x+6x$

$\mathrm{Simplify}$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

Result:

Therefore, from the above calculations it is clear that, the linear equation

$5x+12=5x-7$ has no solution.

4 0

3 years ago

A=1/2bh for b<img src="https://tex.z-dn.net/?f=a%3D1%2F2bh%20for%20b" id="TexFormula1" title="a=1/2bh for b" alt="a=1/2bh for b"

valkas [14]

Times both sides by 2
$2A=bh$
divide both sides b h
$\frac{2A}{h}=b$
$b=\frac{2A}{h}$

5 0

3 years ago

The formula for the equation describing a straight line is y = b0 + b1x. the value for b1 in this equation represents the ______

Rasek [7]

Equation of a straight line is normally in the form: y = mx + c.

Where, m and c are constants in which;
m = gradient
c = y-intercept.

Comparing this standard way way of writing the equation of a straight line with the current scenario, this equation can be rewritten as;
y = b1x + b0.

This way, b1 = gradient of the line while b0 = y-intercept.

4 0

3 years ago