Answer:
See below
Step-by-step explanation:
Vertical velocity will be affected by gravity in this scenario
df = do + vo t + 1/2 a t^2 do = original height = 4 ft a = -32.2 ft/s^2
<u>df = 4 + 89 t - 1/2 (32.2) t^2 df = height</u>
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On the way up and the way down, the ball may reach height of 102.2125 ft :
102.2125 = 4 + 89 t - 1/2 (32.2) t2 re-arrange to:
-16.1 t^2 + 89t - 98.2125 =0
Use Quadratic Formula to find <u>t = 1.5 and 4.0 s </u>
Answer:
Step-by-step explanation:
let p¼ = a, q¼ = b
L.H.S. = (a - b)(a + b)(a² + b²) = (a² - b²)(a² + b²) = (a²)² - (b²)² = p - q = R.H.S.
You need to expand the brackets eg.
(w-9)8 basically means 8 x (w-9) = 8w-72
21*10=210
30*7=210
42*5=210
14*15=210
