Answer:
Step-by-step explanation:
hello : write this expression
X² + y² + 6x – 2y+3 = 0 in the standard form
(x²+6x) +(y²-2y) +3 = 0
(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0
(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0
(x+3)²+(y-1)² = 7(the standard form)
but : 7 = (√7)²
<h2>the radius is :
√7</h2>
Answer:
- 34 < x < 10
Step-by-step explanation:
Inequalities of the type | x | < a, always have a solution of the form
- a < x < a
given | x + 12 | + 5 < 27 ( subtract 5 from both sides )
| x + 12 | < 22, then
- 22 < x + 12 < 22 ( subtract 12 from all 3 intervals )
- 34 < x < 10
There are two ways to do this.
The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34
OR
you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34
Either way, the final answer is 34
Here's the work and the answer. I hope this helps.
Answer: 
Step-by-step explanation:
You need to remember:
1. The Product of powers property: 
2. The Power of a power property: 
In this case, given:
You need to follow these steps in order to simplify it:
1. Apply the Product of powers property:
2. Apply the Power of a power property:
3. Finally, since 
and 
, you get:
