Explanation:
The given data is as follows.
,
Work produced per kJ of heat extracted from hot reservoir = 0.45 kJ = Efficiency
If the device is Carnot cycle then its efficiency will be maximum and its value will be equal to
Using this relation we will calculate the efficiency as follows.
Efficiency =
=
= 0.928
Hence, it means that this type of device is possible and the claim is also believable.
Answer : The heat released by the combustion of 1.121 mol of hexane (kJ) is,
Explanation :
The given balanced reaction is,
Given:
Moles of hexane = 0.121 mol
= -8326 kJ/mol
The negative sign indicate that the reaction exothermic or amount of heat released.
As, 1 mole of hexane released heat = 8326 kJ
So, 0.121 mole of hexane released heat = 8326 × 0.121 = 1007.446 ≈
Therefore, the heat released by the combustion of 1.121 mol of hexane is .
Depth where light intensity falls to one percent<span> of that at the surface, called the euphotic depth</span>
Answer:
Alpha decay is one type of radioactive decay, in which an atomic nucleus emits an alpha particle, and thereby transforms (or "decays") into an atom with a mass number decreased by 4 and atomic number decreased by 2.
Explanation:
Answer:
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