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kogti [31]
3 years ago
5

3.5 x 10^24 ——————— 6.02 x 10^23 How do I solve this exponent function?

Chemistry
1 answer:
kykrilka [37]3 years ago
3 0
I can’t give you the answer right now because I am eating dinner. But I can tell you how to do this. First do 3.5 / 6.02 and then do 10^24 - 10^23 and with that you get your final answer. This is division that's why you had to subtract the exponents.
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The equilibrium constant, K, for the following reaction is 1.80x102 at 698 K. 2HI(9) =H2(g) +129) An equilibrium mixture of the
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Explanation:

The equilibrium constant of the reaction = K_c=1.80\times 10^{-2}

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Initial  concentration:

0.311 M                4.71\times 10^{-2} M           4.71\times 10^{-2} M  

At equilibrium:

(0.485 M - x)  (4.71\times 10^{-2} M+x)           (4.71\times 10^{-2} M+x)  

K_{eq}=\frac{[H_2][I_2]}{[HI]^2}

1.80\times 10^{-2}=\frac{(4.71\times 10^{-2} M+x)\times (4.71\times 10^{-2} M+x)}{ (0.485 M-x)^2}

\sqrt{1.80\times 10^{-2}}=\frac{(4.71\times 10^{-2} M+x)}{ (0.485 M-x)}

0.1342=\frac{(4.71\times 10^{-2} M+x)}{(0.485 M-x)}

0.065087 M-0.1342x=4.71\times 10^{-2} M+x

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x=\frac{0.017987 M}{1.3142}=0.01586 M

Equilibrium concentrations:

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[H_2]=[I_2]=0.06296 M

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