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kogti [31]
3 years ago
5

3.5 x 10^24 ——————— 6.02 x 10^23 How do I solve this exponent function?

Chemistry
1 answer:
kykrilka [37]3 years ago
3 0
I can’t give you the answer right now because I am eating dinner. But I can tell you how to do this. First do 3.5 / 6.02 and then do 10^24 - 10^23 and with that you get your final answer. This is division that's why you had to subtract the exponents.
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Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

PV=nRT

where,

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V = Volume of N_2 gas = 985 mL = 0.982 L    (1 L = 1000 mL)

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Now put all the given values in above equation, we get:

(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K

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Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains 6.022\times 10^{23} number of molecules.

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So, 5.78\times 10^{-11} mole of N_2 gas contains (5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13} number of molecules

Therefore, the number of molecules present in nitrogen gas are, 3.48\times 10^{13}

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