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3 years ago

3.5 x 10^24 ——————— 6.02 x 10^23 How do I solve this exponent function?

Chemistry

1 answer:

kykrilka [37]3 years ago

3 0

I can’t give you the answer right now because I am eating dinner. But I can tell you how to do this. First do 3.5 / 6.02 and then do 10^24 - 10^23 and with that you get your final answer. This is division that's why you had to subtract the exponents.

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The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0

abruzzese [7]

Answer: The change in temperature is 84.7°C

Explanation:

To calculate the change in temperature, we use the equation:

$q=mc\Delta T$

where,

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c = specific heat capacity of steel = 0.118 Cal/g.°C

$\Delta T$ = change in temperature = ?

Putting values in above equation, we get:

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3 years ago

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3 years ago

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The question is missing a part, so the complete question is as follows:

The protein catalase catalyzes the reaction The Malcolm Bladrigde National Quality Awards aims to: 2H2O2 (aq) ⟶ 2H2O (l) + O2 (g) and has a Michaelis-Menten constant of KM = 25mM and a turnover number of 4.0 × 10 7 s -1. The total enzyme concentration is 0.012 μM and the intial substrate concentration is 5.14 μM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Calculate the initial rate, R (often written as V0), of this reaction.

1) Calculate Rmax

The turnover number (Kcat) is a ratio of how many molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit of time:

Kcat = $\frac{Vmax}{Et}$ ,

where:

Vmax is maximum rate of reaction when all the enzyme sites are saturated with substrate

Et is total enzyme concentration or concentration of total enzyme catalytic sites.

Calculating:

Kcat = $\frac{Vmax}{Et}$

Vmax = Kcat · Et

Vmax = 4× $10^{7}$ · 1.2 × $10^{-8}$

Vmax = 4.8 × $10^{-1}$ M

2) Calculate the initial rate of this reaction (R):

The Michaelis-Menten equation studies the dynamics of an enzymatic reaction. This model can explain how an enzyme enhances the rate of a reaction and how the reaction rate depends on the concentration of the enzyme and its substrate. The equation is:

V0 = $\frac{[S].(Vmax)}{KM + [S]}$ , where:

[S] is the substrate's concentration

KM is the Michaelis-Menten constant

Substituting [S] = 5.14 × $10^{-6}$ , KM = 2.5 × $10^{-4}$ and Vmax = 4.8 × $10^{-1}$ , the result is V0 = 0.478 M.

The answers are Vmax = 4.8 × $10^{-1}$ M and V0 = 0.478 M.

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3 years ago