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AVprozaik [17]
3 years ago
13

Find the slope of each line (no links I’ll report)

Mathematics
1 answer:
kaheart [24]3 years ago
7 0

Answer:

Slope = ⁵/7

Step-by-step explanation:

Slope (m) = change in y / change in x

Using two points on the graph, (-4, -4) and (3, 1),

Slope (m) = (1 - (-4))/(3 - (-4)) = 5/7

Slope (m) of the line = 5/7

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A cylinder had a diameter of 17 cm and a height of 11 cm. ehat is the volume of the cylinder​
tester [92]

Answer:

2496.78

Step-by-step explanation:

7 0
3 years ago
Express each number in its simplest radical form. <br> √6⋅√60=?
Tom [10]

Answer:

6√10

Step-by-step explanation:

factorizing 6 and 60

6 =  2 x 3

60 = 2 x 2 x 3 x 5

hence

√6 · √60

= √ [ (2 x 3) · (2 x 2 x 3 x 5) ]

= √ (2· 2² · 3² · 5)

= √ (2² · 3²) x √(2·5)

= (2 · 3) x √10

= 6√10

5 0
3 years ago
Read 2 more answers
G evaluate the given integral by changing to polar coordinates. e−x2 − y2 da d where d is the region that lies to the left of th
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7 0
3 years ago
In 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alc
Fynjy0 [20]

Answer:

We conclude that the proportion of adults who totally abstain from alcohol​ has changed.

Step-by-step explanation:

We are given that in 1943​, an organization surveyed 1100 adults and​ asked, "Are you a total abstainer​ from, or do you on occasion​ consume, alcoholic​ beverages?"

Of the 1100 adults​ surveyed, 429 indicated that they were total abstainers. In a recent​ survey, the same question was asked of 1100 adults and 352 in

<u><em>Let p = proportion of adults who totally abstain from alcohol.</em></u>

where, p = \frac{429}{1100} = 0.39

So, Null Hypothesis, H_0 : p = 39%      {means that the proportion of adults who totally abstain from alcohol​ has not changed}

Alternate Hypothesis, H_A : p \neq 39%      {means that the proportion of adults who totally abstain from alcohol​ has changed}

The test statistics that would be used here <u>One-sample z proportion statistics</u>;

                    T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who totally abstain from alcohol = \frac{352}{1100} = 0.32

           n = sample of adults surveyed = 1100

So, <u><em>test statistics</em></u>  =  \frac{0.32-0.39}{\sqrt{\frac{0.32(1-0.32)}{1100} } }  

                              =  -4.976

The value of z test statistics is -4.976.

<em>Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.</em><em> </em>

<em>Since our test statistics doesn't lie within the range of  critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the proportion of adults who totally abstain from alcohol​ has changed.

4 0
3 years ago
Suppose the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars
GuDViN [60]

Answer:

Probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

Step-by-step explanation:

We are given that the mean income of firms in the industry for a year is 95 million dollars with a standard deviation of 5 million dollars. Also, incomes for the industry are distributed normally.

<em>Let X = incomes for the industry</em>

So, X ~ N(\mu=95,\sigma^{2}=5^{2})

Now, the z score probability distribution is given by;

         Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean income of firms in the industry = 95 million dollars

            \sigma = standard deviation = 5 million dollars

So, probability that a randomly selected firm will earn less than 100 million dollars is given by = P(X < 100 million dollars)

    P(X < 100) = P( \frac{X-\mu}{\sigma} < \frac{100-95}{5} ) = P(Z < 1) = 0.8413   {using z table]

                                                     

Therefore, probability that a randomly selected firm will earn less than 100 million dollars is 0.8413.

5 0
3 years ago
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