If we were to plot the points on a graph, we could draw a straight lint between them. The question wants us to find the length of this line. We could make a right triangle with this line as the hypotenuse, with an x length of 2(y2-y1) and a y length of 5 (y2-y1). From there we can find the hypotenuse with Pythagorean Theorem: c^2=a^2+b^2.
c^2=(2)^2+(5)^2
c^2=4+25
C^2=41
c=

Decimal approximation: 6.403
Hope this helps!
Answer:
z = 120º
Step-by-step explanation:
t + 2t + t + 2t = 360º
60 + 2(60) + 60 + 2(60) = 360
t = 60
2t = z
z = 120º
This is all based on the fact there there are 360º in a quadrilateral.
∠B = 77°, a = 7.42 and b = 12.61
Solution:
Given triangle ABC.
∠A = 35°, ∠C = 68°, c = 12
To find the measure of ∠B:
Sum of all the angles of the triangle = 180°
⇒ ∠A + ∠B + ∠C = 180°
⇒ 35° + ∠B + 68° = 180°
⇒ 103° + ∠B = 180°
⇒ ∠B = 180° – 103°
⇒ ∠B = 77°
To find the length of a and b:
The side opposite to angle A is a.
The side opposite to angle B is b.
Using law of sine,



Do cross multiplication, we get

Divide by 0.9271 on both sides, we get
⇒ a = 7.42
Again by law of sine,



Do cross multiplication, we get

Divide by 0.9271 on both sides, we get
⇒ b = 12.61
Hence ∠B = 77°, a = 7.42 and b = 12.61.