The first one is the 5th tile and the second one is the 3rd tile
First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8
h = 256*8 - 16*8^2
h = 1024
Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0
t1 = 0.82s
t2 = 15.17s
time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
Answer:
The answer is x=27/28
Step-by-step explanation:
Solve for x by simplifying both sides of the equation, then isolating the variable.
20 didn't do it for this one.
