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docker41 [41]
3 years ago
7

Help plzzz... circle geometry question.

Mathematics
1 answer:
Elodia [21]3 years ago
7 0

Answer:

IU = 161

Step-by-step explanation:

Angle Formed by Two Secants=  1/2 (difference of Intercepted Arcs)

42 = 1/2 (7m+5 - (3m-1))

Distribute the minus sign

42 = 1/2 (7m+5 - 3m+1))

Combine like terms

42 = 1/2 ( 4m+6)

Distribute the 1/2

42 = 2m+3

Subtract 3 from each side

42-3 = 2m+3-3

39 = 2m

Divide by 2

19.5 = m

The sum of the arcs = 360

IU+ 3m-1 + 7m+5 = 360

IU +10m+4 = 360

IU +10(19.5) +4 = 360

IU +195+4 = 360

IU = 360 - 199

IU=161

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The energy required is 30 watts second.

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Now, energy can be defined as the product of voltage and charge.

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E = 30 watt second

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2 years ago
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use the trigonometric values table or unit circle to calculate the expression

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ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually g
mr Goodwill [35]

Answer:

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Step-by-step explanation:

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If Professor Wilson found that the test scores of his students had a variance of 4.4, what is the standard deviation? Type a num
malfutka [58]

Answer:

The standard deviation will be: 2.1        

Step-by-step explanation:

We know that standard deviation is basically the square root of variance.

Using the formula to calculate the standard deviation

s=\sqrt{s^2}

As

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so the standard deviation can be calculated as:

standard deviation =\sqrt{s^2}

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8 0
3 years ago
The approximate height, h, in meters, traveled by golf balls hit with two different clubs over a horizontal distance of d meters
inna [77]

Answer:

a) 100 metres

b) 10 metres

Step-by-step explanation:

Given: the approximate height, h, in meters, travelled by golf balls hit with two different clubs over a horizontal distance of d meters is given by the functions: h=-0.002d^2+0.3d\,,\,h=-0.004d^2+0.5d

To find: distances when the ball is at the same height when either of the clubs  are used. Also, to find this height

Solution:

(a)

-0.002d^2+0.3d=-0.004d^2+0.5d\\d(-0.002d+0.3)=d(-0.004d+0.5)\\-0.002d+0.004d=0.5-0.3\\0.002d=0.2\\d=\frac{0.2}{0.002}=100\,\,metres

(b)

Put d = 100 in h=-0.002d^2+0.3d

h=-0.002(100)^2+0.3(100)\\=-20+30\\=10\,\,metres

4 0
3 years ago
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