9514 1404 393
Answer:
21 coins of ₹2
Step-by-step explanation:
Let x represent the number of ₹2 coins, and y the number of ₹5 coins. Then the total value of the coins is ...
2x +5y = 77
and the relationship between numbers of coins is ...
x = 3y
Substituting for x, we have ...
2(3y) +5y = 77
y = 77/11 = 7 . . . . simplify, divide by the coefficient of y
x = 3(7) = 21 . . . . find x from the second equation
Ram has 21 of the ₹2 coins.
2 4/8 x 3 = 7 4/8
11 3/8 - 7 4/8 = 3 7/8 miles from the end
1) idk I got none of your options
2)p=42,000÷(1+0.0225÷12)^(12×5)
P=37,535.04
3)PVAO=4900*12[(1/0.029)-(1/0.029*(1+0.029)^10]=504145.41..compare with 500000
So the answer is D
4)lucas
90×87.92=7,912.8
((8,476.20−7,912.8)
÷7,912.8)×100=7.1%
Peton
55×72.03=3,961.65
((4,192.10−3,961.65)
÷3,961.65)×100=5.8%
So the answer is D
MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90
<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120
answer
<CDE = 120°
(4v-3w)∧2, Its to the second power so take the exponent 2 and put it on the variables and coefficients so you would have (4∧2)(v∧2)-(3∧2)(w∧2). Then you would do the math and get 16v∧2-9w∧2 than you would add the like terms so you have 25v∧2w∧2.
