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eimsori [14]
3 years ago
10

What is the value of 1/3 x^2 + 5.2y when x = 3 and y = 2? PLZ HELP!!!

Mathematics
1 answer:
olasank [31]3 years ago
6 0
The first step in solving this is to substitute x with 3 and y with 2, so that
\frac{1}{3} x^{2} +5.2y
becomes
\frac{1}{3}  (3)^{2} +5.2(2)
Then simply solve using the order of operations.
First exponents (there are no parentheses)
\frac{1}{3} 9 +5.2(2)
Then multiply and divide
3+10.4
And finally add and subtract
13.4
Therefore the value <span>of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4</span>
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Let X the random variable that represent the runtimes of a population, and for this case we know the distribution for X is given by:

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