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eimsori [14]
3 years ago
10

What is the value of 1/3 x^2 + 5.2y when x = 3 and y = 2? PLZ HELP!!!

Mathematics
1 answer:
olasank [31]3 years ago
6 0
The first step in solving this is to substitute x with 3 and y with 2, so that
\frac{1}{3} x^{2} +5.2y
becomes
\frac{1}{3}  (3)^{2} +5.2(2)
Then simply solve using the order of operations.
First exponents (there are no parentheses)
\frac{1}{3} 9 +5.2(2)
Then multiply and divide
3+10.4
And finally add and subtract
13.4
Therefore the value <span>of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4</span>
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It takes a train 60 seconds to completely drive through a bridge of 1260 m, and 90 seconds to completely drive through a tunnel
Olegator [25]

The length of train is 120 meters

The speed of train is 25 meter per second

<u><em>Solution:</em></u>

The speed is given by formula:

speed = \frac{distance}{time}

Given that,

It takes a train 60 seconds to completely drive through a bridge of 1260 m

And 90 seconds to completely drive through a tunnel of 2010 m

Let the length of the train be "x"

<em><u>The total distance travelled by the train across the bridge is given by:</u></em>

total distance = x + 1260 + x = 2x + 1260

[ here we use x + x to represent that train completely drives through bridge ]

The time taken is given as 60 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 1260}{60}

<em><u>The total distance travelled by the train through the tunnel is given by:</u></em>

total distance = x + 2010 + x = 2x + 2010

The time taken is given as 90 seconds

<em><u>Therefore, the speed is given as:</u></em>

speed = \frac{2x+ 2010}{90}

The speed of the train was the same in both cases.

Equate both speeds

\frac{2x+ 1260}{60} = \frac{2x+ 2010}{90}

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Thus length of train is 120 meters

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speed = \frac{2x+ 1260}{60}\\\\speed = \frac{2(120) + 1260)}{60}\\\\speed = 25

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