What is the value of 1/3 x^2 + 5.2y when x = 3 and y = 2? PLZ HELP!!!

1 answer:

6 0

The first step in solving this is to substitute x with 3 and y with 2, so that
$\frac{1}{3} x^{2} +5.2y$
becomes
$\frac{1}{3} (3)^{2} +5.2(2)$
Then simply solve using the order of operations.
First exponents (there are no parentheses)
$\frac{1}{3} 9 +5.2(2)$
Then multiply and divide
$3+10.4$
And finally add and subtract
$13.4$
Therefore the value <span>of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4</span>

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