The total space in the parking lot is 1600 cars
It is mentioned that 
parts of this parking is filled
Now we are required to find what is the three-fourths part of 1600
To find it we multiply times 1600
= 
=
= 1200 cars
Hence 1200 cars fills the three-fourths of the car parking lot that has a capacity of 1600 cars
<h2>
Answer:<em>
</em><em><u>
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
</u></em></h2><h2><em><u>
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>
Step-by-step explanation: The prime factorization of 4320 is
2•2•2•2•2•3•3•3•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 4320 = √ 2•2•2•2•2•3•3•3•5 =2•2•3•√ 30 =
± 12 • √ 30
√ 30 , rounded to 4 decimal digits, is 5.4772
So now we are looking at:
w = ( -40 ± 12 • 5.477 ) / -34
Two real solutions:
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757
or:
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
MY HEAD HURTS!
Answer: 184
Step-by-step explanation:
The nth term of am arithmetic sequence is calculated as:
Nth term= a+(n-1)d
where a = first term
d = common difference
a = -10
d = -8 -(-10) = -8+10 = 2
98th term= a+(n-1)d
= -10 + (98-1)(2)
= -10 + (97×2)
= -10 + 194
= 184
The 98th term of the arithmetic sequence is 184
Answer:
3. They're adding by 5 so,
Step-by-step explanation:
