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3 years ago

What is the value of 5(a-4b) when a= -7 and b= 0.25

Mathematics

1 answer:

Tom [10]3 years ago

5 0

Answer:

-40

Step-by-step explanation:

5(-7-4[0.25])

5(-7-1)

-35-5

-40

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Adam is building a rectangular planter without a top the planter will be 7 feet wide 5 feet wide, 5 feet long, and 9 inches high

Tom [10]

Answer: The surface area of the planter will be 120.5 square feet.

In our shape, we will have 5 sides. The base and the four sides going up from each edge of the base.

The base will be 7 x 5 = 35 square feet.

The front and back side will each be 7 x 0.75 = 5.25 square feet.

The left and right side will each be 5 x 0.75 = 3.75 square feet.

If we add up the 5 faces we get:
35 + 5.25 + 5.25 + 3.75 + 3.75 = 120.5 square feet

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3 years ago

Is this function linear or nonlinear?

Sergio039 [100]

The answer is nonlinear. It goes in a sharp downward curve, whereas a linear function is a straight line.

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3 years ago

Complete the equation of this circle: А (x – [? ])2+(y - [ ])2= [ ]

pashok25 [27]

Answer:

$r = \sqrt{ {2}^{2} + {2}^{2} - 3 } = 5 \\ {(x - 2)}^{2} + {(y - 2)}^{2} = 3$

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3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$