Quadrilateral ABCD has vertices A(1, 0) B(5, 0) C (7, 2) D(3, 2). Use slope to prove that ABCD is a parallelogram.

1 answer:

7 0

If ABCD is a parallelogram, we have to prove that slope of AB = CD and slope of BC = DA. Using the formula m = (y1-y2) / (x1-x2), the slope of line segment AB = 0/-4, CD = 0/-4, BC = 1, DA = 1. Going back to the condition, the slope we get for each line segment proves that ABCD is a parallelogram.

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HELP. It’s LOG form. Since were out of school I forgot how I did this and it’s due so it would be a life saver.

____ [38]

Answer:

see below

Step-by-step explanation:

exponent to log: $a^b$ = c ---> logₐc = b

ie. question 6

log ₁₀(3x+1) = 2 -----> $10^{2} = 3x+1$

that will get you through questions 1 to 3, 5 to 6, and 8

in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3

for questions 7 and 9,

remember that:

logₐc + logₐd = logₐ(cd)

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remember change of base is $log_{a} b = \frac{log_xb}{log_xa}$ , this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e