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Bess [88]
3 years ago
5

A company that specializes in language tutoring lists the following information concerning its English-speaking employees: 23 em

ployees speak German; 29 speak French; 33 speak Spanish; 43 speak Spanish or French; 38 speak French or German; 48 speak German or Spanish; 8 speak Spanish, French, and German; and 7 speak English only. (Round your answer to one decimal place.)
(a) What percent of the employees speak at least one language other than English?


(b) What percent of the employees speak at least two languages other than English?
Mathematics
1 answer:
galben [10]3 years ago
5 0
I assume the sentences:
"23 employees speak German; 29 speak French; 33 speak Spanish"
mean these speak ONLY the respective languages other than English.
Then the calculations boil down to those who speak ONLY two languages, noting that 8 speak French, German and Spanish, which need to be subtracted from 
1. French and Spanish: 43-8=35 (speak only two foreign languages)
2. German and French: 38-8=30 (speak only two foreign languages)
3. German and Spanish: 48-8=40 (speak only two foreign languages).

Now We add up the total number of employees:
zero foreign language = 7
one foreign language  = 23+29+33=85
two foreign languages = 30+35+40=105
three foreign languages=8
Total =7+85+105+8=205

(a) Percentage of employees who speak at least one foreign lanugage = (85+105+8)/205=198/205=.966=96.6%
(b) Percentage of employees who speak at least two foreign lanugages = (105+8)/205=113/205=.551=55.1%
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2 years ago
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60, 60, 65, 70, 70, 85, 90

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3 years ago
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We can find the probability of interest using the normal standard table and with the following difference:

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And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

P(38.6

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

z=\frac{X -\mu}{\sigma}

And replacing we got:

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