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pshichka [43]
3 years ago
12

Let E be the event that a corn crop has an infestation of ear worms, and let B be the event that a corn crop has an infestation

of corn borers. Suppose that P(E) = 0.24, P(B) = 0.16, and P(E and B) = 0.13. Find the probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both.
Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

The probability that a corn crop has either an ear worm infestation, a corn borer infestation

P(EUB) = 0.27

Step-by-step explanation:

<u>Explanation</u>:-

<u>Addition theorem on probability</u>:-

If S is a sample space, and E , F are any events in S then

P(EUF) = P(E) +P(F) -P(E n F)

Let 'E' be the event that a corn crop has an infestation of ear worms

let 'B' be the event that a corn crop has an infestation of corn bores

P(EUB) = P(E) +P(B) -P(E n B)

given P(E) = 0.24 and P(B) = 0.16 and P(E n B) =0.13

P(EUB) = P(E) +P(B) -P(E n B)

P(EUB) = 0.24 + 0.16 - 0.13

           = 0.27

The probability that a corn crop has either an ear worm infestation, a corn borer infestation

P(EUB)=0.27

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