That statement is true.
In recent technologies, folder can contain whatever users want it to contain. Not only, that, users could also arrange the maximum size of files that a folder could contain or the visibility status of each items that will be placed on the shoulder in case they need some sort of privacy for his/her files
Answer: Planning the solution, look and feel of the software interface
Answer:
Push Z
Push Y
Pop Y
Push X
Pop X
Push W
Push V
Pop V
Push U
Pop U
Pop W
Pop Z
Push T
Push S
Pop S
Push R
Pop R
Pop T
Explanation:
A stack is a term in computer science that defines an abstract data type that acts as a collection of elements. It has two operations which are mainly push and pop.
Push is used in adding elements to the collection, while pop is used in removing elements from the collection.
If the element A has been pushed to the stack, you check if the top element in the pop[] sequence is A or not.
If it is A, you then pop it right, else top of the push[] sequence will be changed and make the sequences invalid.
So, similarly do the same for all the elements and check if the stack is empty or not in the last.
If empty you then print True else print False.
Answer:
Check the explanation
Explanation:
Kindly check the attached image.
The attached image below describes the inner equilibrium point is a stable node, here it's a center. These are periodic solutions. Populations of the mice and owls are periodic. It describes: when the mice population is lower, the owl population decreases; again the owl is lower so mice got a chance to grow its population; now as sufficient food(mice) is there, the owl population increases; as predator population increases, the prey population decreases; and this continues as a cycle forever.
So, yes, the model gives a realistic behavior.
Answer:
words.hasNext()
Explanation:
Given the code snippet below:
- while (inputFile.hasNextLine()) {
- String word = "";
- String line = inputFile.nextLine();
- Scanner words = new Scanner(line);
- while (words.hasNext()) {
- word = words.next();
- }
- System.out.println(word); }
- }
We have a inputFile Scanner object that can read data from a text file and we presume the inputFile has read several rows of data from the text file. So long as there is another line of input data available, the outer while loop will keep running. In each outer loop, one line of data will be read and assign to line variable (Line 3). Next, there is another Scanner object, words, which will take the current line of data as input. To get the last word of that line, we can use hasNext() method. This method will always return true if there is another tokens in its input. So the inner while loop will keep running so long as there is a token in current line of data and assign the current token to word variable. The word will hold the last token of current line of data upon exit from the inner loop. Then we can print the output (Line 8) which is the last word of the current line of data.
