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AleksAgata [21]
3 years ago
15

A user calls to complain that her computer is behaving erratically. Some days it functions correctly, and other days, it crashes

frequently. Sometimes, the system won't boot at all. You open the system case and notice the following: Two of the mounting screws are missing from the system hard disk drive. The system uses memory modules from several different manufacturers with mismatched capacities. Several capacitors on the motherboard are bulging and have a brown liquid oozing from them. The chassis fan on the front of the case is oriented to blow air into the system. What should you do
Computers and Technology
1 answer:
Hitman42 [59]3 years ago
5 0

Answer:

Replace the motherboard.

Explanation:

The motherboard is the core of the computer. If the motherboard is oozing brown stuff, signifying that one of the sectors has been eroded or is about to disrupt, it needs to be replaced before further damage can be made.

The screws in the hard drive can easily be replaced.

As for the memory sticks, they will operate best if they were the same brand and the same memory size and hertz.

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The means by which an operating system or any other program interacts with the user is called th
natulia [17]
Networking capabilities of a computer
7 0
3 years ago
Design a program takes as input, X, an unsorted list of numbers, and returns the sorted list of numbers in X. The program must b
Lelechka [254]

Answer:

The program in python is as follows:

def split(X):

   L = []; G = []

   for i in range(len(X)):

       if X[i]>=X[0]:

           G.append(X[i])

       else:

           L.append(X[i])

   L.sort(); G.sort()

   return L,G

X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

   print(X)

else:

   X1,X2=split(X)

   newList = sorted(X1 + X2)

   print(newList)

Explanation:

The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

<em>    print(X)</em>

If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

7 0
3 years ago
2.Consider the following algorithm and A is a 2-D array of size ???? × ????: int any_equal(int n, int A[][]) { int i, j, k, m; f
Elis [28]

Answer:

(a) What is the best case time complexity of the algorithm (assuming n > 1)?

Answer: O(1)

(b) What is the worst case time complexity of the algorithm?

Answer: O(n^4)

Explanation:

(a) In the best case, the if condition will be true, the program will only run once and return so complexity of the algorithm is O(1) .

(b) In the worst case, the program will run n^4 times so complexity of the algorithm is O(n^4).

5 0
4 years ago
Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the gas cost for 10 miles, 5
omeli [17]

Answer:

The Following are the code to this question:

def cost(miles, milesPerGallon, dollarsPerGallon):##defining a method cost that accepts three parameter

   return miles / milesPerGallon * dollarsPerGallon# calculate cost and return it value  

milesPerGallon = float(input('Enter miles/Gallon value: '))#defining variable milesPerGallon for user input  

dollarsPerGallon = float(input('Enter dollars/ Gallon value: '))#defining variable dollarsPerGallon for user input

print('{:.5f}'.format(cost(10, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.5f}'.format(cost(50, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.3f}'.format(cost(400, milesPerGallon, dollarsPerGallon)))#call method and print its value

Output:

Enter miles/Gallon value: 20.0

Enter dollars/ Gallon value: 3.1599

1.57995

7.89975

63.198

Explanation:

In the above-given code, a method "cost" is defined, that accepts three value "miles, milesPerGallon, and dollarsPerGallon" in its parameter, and use the return keyword for calculating and return its value.

In the next step, two variable "milesPerGallon, and dollarsPerGallon" is declared, that use the input method with float keyword for input floating-point value.

After input value, it uses a print method with different miles values, which are "10,50, and 400", and input value to pass in cost method to call and print its return value.

5 0
3 years ago
What is the easiest way to create a diverse set of cover pages?<br><br> Word 2016
Sindrei [870]

Answer:

using the cover page gallery

Explanation:

This is certainly the easiest way. And you just need to add this as first page, set the borders, pagination, headers and footers from second page, and avoiding the first page as it is the cover page as well as customize the various section of the cover page design you choose.

Inserting a blank page will require a lot of effort.

Inserting pictures will not  result into a complete and a meaningful cover page.

Same is the case if you insert shapes.

hope it helps :)

3 0
3 years ago
Read 2 more answers
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