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Gnoma [55]
3 years ago
13

Why is experience in their own factory setting

Computers and Technology
1 answer:
Nataly [62]3 years ago
5 0

Answer:

How to Manage Manufacturing Operations Effectively

Ensure High-Quality Products. ...

Ensure High-Quality Equipment. ...

Know How To Maximize Resources. ...

Look Into Technological Advancements. ...

Check Your Customer Service. ...

Consider Reducing Waste. ...

Conclusion.

Explanation:

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Give a real life of an if statement
bogdanovich [222]

Answer:

If Joe wants to eat an apple then he eats an apple.

Explanation:

The if statement checks if Joe "wants to eat an apple", if it turns out he does not then nothing will happen.

7 0
3 years ago
A device that makes it possible for multiple customers to share one address is called a/n _____.
Debora [2.8K]
When you use the word "address", I assume you are referring to an external address, in which case the answer is NAT (network address translation). Essentially, network address translation converts LAN IP addresses (local IP addresses) to WAN  IP addresses (external IP addresses). So for instance: everyone in my home accesses the internet under our network's external IP address. Inside our network, we have local IP addresses, which allow for packets to be routed to our individual machines wirelessly. So let's say my IP address on the LAN is 192.168.1.4, and I want to access brianly.com. My router performs NAT by converting my local IP to an external one which can be used for accessing the web. Then when data comes back to the network from brainly's server, my router once again performs NAT to convert between my external IP to my local IP, so that my router knows where the data needs to be routed to on the LAN.
6 0
3 years ago
Which components exist in the contextual tab for tables called Design? Check all that apply. Table Styles Export Table Data Prop
EastWind [94]

Answer: table styles, properties, tools, external table data, table style options

Explanation: i took the assignment

4 0
3 years ago
Read 2 more answers
after clicking the start button on your computer screen desktop what option would you then select to examines system components
crimeas [40]
Assuming you're using Windows, you have to search for the application Device Manager. It will show you all connected devices on your system, as well as an option to modify drivers and certain options. 
3 0
3 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
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