you can use a vpn (virtual proxy network) that is the easiest way and the fastest
Answer:
the user should disable file and print sharing on the laptop
Explanation:
According to my research on information technology and cyber security, I can say that based on the information provided within the question in order to prevent this the user should disable file and print sharing on the laptop. This is because this file and printer sharing allows users to see your files that you have available as shared and copy or print those files. Which if they are sensitive data you should just disable this option so that people on the same network cannot see or access these files.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
(a) someFunc(3) will be called 4 times.
(b) For non negative number n someFunc method calculates 2^2^n.
Explanation:
When you call someFunc(5) it will call someFunc(4) two time.
So now we have two someFunc(4) now each someFunc(4) will call someFunc(3) two times.Hence the call to someFun(3) is 4 times.
someFunc(n) calculates someFunc(n-1) two times and calculates it's product.
someFunc(n) = someFunc(n-1)^2..........(1)
someFunc(n-1)=someFunc(n-2)^2..........(2)
substituting the value form eq2 to eq 1.
someFunc(n)=someFunc(n-2)^2^2
.
.
.
.
= someFunc(n-n)^2^n.
=2^2^n
2 raised to the power 2 raised to the power n.
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
