Answer:
11. your choices are correct
12. 132°
Step-by-step explanation:
11. The given equations can be (re)written to slope-intercept form. Only those lines with a slope of 2 will be parallel to the given line.
A: y = 2x -8 . . . . . slope = 2, an answer
B: y = -2x +1 . . . . . slope = -2, not an answer
C: y = -2x +7 . . . . .slope = -2, not an answer
D: y = 2x +2 . . . . . slope = 2, an answer
E: y = -2x -9 . . . . . slope = -2, not an answer
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12. The marked angles are supplementary, so ...
(3x -6)° +(x +2)° = 180°
4x -4 = 180 . . . . . . . . . . . divide by °, collect terms
x -1 = 45 . . . . . . . divide by 4
x = 46 . . . . . . . . . add 1
Now, we can find the angle of interest.
∠PQR = (3x -6)° = (3·46 -6)°
∠PQR = 132°
If you want the angle it’s 22
In all triangles the angles must add up to 180 so 68 + 90 =158 + 22 =180
Once per month there is food that is 33 centimeters long
Answer:
Trampolinist will land on the trampoline after 0.9 seconds.
Step-by-step explanation:
The function h(t) = -16t² + 15 represents the relation between height 'h' above the ground and the time 't' of the trampolinist.
We have to find the time when trampolinist lands on the ground.
That means we have to find the value of 't' when h(t) = 15 - 13 = 2
[Since trampoline is 2 feet above the ground]
When we plug in the value h(t) = 2
2 = -16t² + 15
2 + 16t² = -16t² + 16t² + 15
16t² + 2 = 15
16t² + 2 - 2 = 15 - 2
16t² = 13
t = 
t ≈ 0.9 seconds
Therefore, trampolinist will land on the trampoline at 0.9 seconds.
Answer:
y=-8/5x+77/5
Step-by-step explanation:
The equation of line that passes through the points (4, 9) and (9, 1) is y=-8/5x+77/5. Hope it helps!
