This Question: 1 pt

Mathematics

1 answer:

irinina [24]2 years ago

6 0

Answer:

i would say $148.80

Step-by-step explanation:

tax would amount to 11.20 so when you subyract that from the total then the rest is what she can spend.

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Suppose that a number written as a decimal has an infinite number of non–repeating digits after the decimal point. what is this

marishachu [46]

This kind of number is known as an irrational number

7 0

3 years ago

How to solve this problem

Marysya12 [62]

0.5(x - 3) + (1.5 - x) = 5x
0.5x - 1.5 + 1.5 - x = 5x
-0.5x = 5x
5x + 0.5x = 0
5.5x = 0
x = 0

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2 years ago

10 POINTS !

sesenic [268]

Gradient= -3/2 Equation: Y=mx+c Y=2 , X=8

So you substitute the numbers in

2=(-3/2) x 2 + c (then you backtrack to solve for c which is the y intercept)

2=-3+c

5=c So the equation should be Y=-3/2x+5

5 0

3 years ago

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What is t+8=15 write how u found out show ur work thanx plz hellppppp

Pachacha [2.7K]

The answer is the number that 't' must be in order for the equation
to be a true statement.

Here's how to find it:

Write t + 8 = 15

Then subtract 8 from each side: <em> t = 7</em>

8 0

3 years ago

Read 2 more answers

Rationalize the numerator. <br><img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B144x%20%7D%20%7D%7B%20%5Csq

Simora [160]

rationalizing the numerator, or namely, "getting rid of that pesky radical at the top".

we simply multiply top and bottom by a value that will take out the radicand in the numerator.

$\bf \cfrac{\sqrt[3]{144x}}{\sqrt[3]{y}}~~
\begin{cases}
144=2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 3\\
\qquad 2^3\cdot 18
\end{cases}\implies \cfrac{\sqrt[3]{2^3\cdot 18x}}{\sqrt[3]{y}}\implies \cfrac{2\sqrt[3]{ 18x}}{\sqrt[3]{y}}
\\\\\\
\cfrac{2\sqrt[3]{ 18x}}{\sqrt[3]{y}}\cdot \cfrac{\sqrt[3]{(18x)^2}}{\sqrt[3]{(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)(18x)^2}}{\sqrt[3]{(y)(18x)^2}}\implies \cfrac{2\sqrt[3]{(18x)^3}}{\sqrt[3]{18^2x^2y}}$

$\bf \cfrac{2(18x)}{\sqrt[3]{324x^2y}}~~
\begin{cases}
324=2\cdot 2\cdot 3\cdot 3\cdot 3\cdot 3\\
\qquad 12\cdot 3^3
\end{cases}\implies \cfrac{36x}{\sqrt[3]{12\cdot 3^3x^2y}}
\\\\\\
\cfrac{36x}{3\sqrt[3]{12x^2y}}\implies \cfrac{12x}{\sqrt[3]{12x^2y}}$

3 0

3 years ago

Read 2 more answers