3 years ago

Round the number to the nearest tenth 3.9(x - 6.9) = 24.95

Mathematics

1 answer:

Mazyrski [523]3 years ago

8 0

The answer to the problem is 13.30

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Determine whether each pair of expressions is equivalent.show your work. 4p + 3c and (c +2p)(2)

shtirl [24]

Answer:

Not equivalent

Step-by-step explanation:

4p + 3c

(c + 2p)(2)

2c + 4p

No equal

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3 years ago

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musickatia [10]

Answer:

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30+2x+7+63=180

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2x=180-100

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andrey2020 [161]

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3 years ago

Using the Quotient of Powers Property Simplify 12x^9/2x^3 6x^2 6x^6 10x^3 10x^6

AysviL [449]

Answer:

It is 6x^6 ... since you divide 12÷2=6 and you subtract exponents

3 0

3 years ago

What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x

lora16 [44]

$\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}$

We can begin by rearranging this into multiplication:

$\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}$

Now we can factor the numerators and denominators:

$\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}$

The factors (x+4) and (x+2) cancel out, leaving us with:

$\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}$

Our answer comes out to be:

$\frac{(x-4)^{2} }{(x+3)(x+1)}$ or $\frac{ x^{2} -8x+16}{ x^{2}+4x+3 }$

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4

4 0

3 years ago