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WINSTONCH [101]
3 years ago
13

Utop you answer questions 8:10. Each unit on the graph represents 0.75 miles Round

Mathematics
2 answers:
Kitty [74]3 years ago
8 0

Answer:

6: 15miles

7: 17miles

8: No, because just by going to the grocery is 13miles (times2) that's 26

9: 11.2 (not sure)

10: No, he said 5miles, the park is 5.8miles away from his house. (you don't have to but rounded is 6miles so he cant reach the park)

Step-by-step explanation:

<h3>Use the formula of a²+b²=c² (Pythagorean theorem)</h3><h3 />
Leya [2.2K]3 years ago
3 0

Answer:

6. 11.3 Miles

7. 1.5 Miles

8. No he would need 26 Miles , he only has 25 Miles.

9. 11.25 Miles

10. Not really it slightly goes over by about .80

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the second answer is 17,183,431,198,720
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A building in a downtown business area casts a shadow that measures 88 meters along the ground. the straight-line distance from
algol [13]
As the building is 88 meters along the around and the shadow makes with a straight line of 32 degrees it would equal 55 meters high.
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3 years ago
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Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
3 years ago
The general form of the equation of a circle is x2+y2−4x−8y−5=0.
valentina_108 [34]

Answer:

centre = (2, 4)

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 4x - 8y - 5 = 0

Rearrange the x/y terms together and add 5 to both sides

x² - 4x + y² - 8y = 5

Use the method of completing the square on both the x/y terms

add ( half the coefficient of the x/y terms )² to both sides

x² + 2(- 2)x + 4 + y² + 2(- 4)y + 16 = 5 + 4 + 16

(x - 2)² + (y - 4)² = 25 ← in standard form

with centre (2, 4) and r = \sqrt{25} = 5

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