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Oxana [17]
3 years ago
6

Write 25*24*23*22 as a quotient of factorials and as a permutation

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

(a)

25\times 24\times 23\times 22=\frac{25!}{21!}

(b)

25\times 24\times 23\times 22=P(25,4)

Step-by-step explanation:

Quotient of factorials:

we are given

25\times 24\times 23\times 22

we can multiply top and bottom term by 21!

25\times 24\times 23\times 22=\frac{25\times 24\times 23\times 22\times 21!}{21!}

we can write as

25\times 24\times 23\times 22=\frac{25!}{21!}

As a permutation:

we know permutation formula

P(n,r)=\frac{n!}{(n-r)!}

now, we can compare and find 'n' and 'r'

n=25

n-r=21

we can plug back n=25

25-r=21

r=4

so, we can write

25\times 24\times 23\times 22=P(25,4)

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Given:

Vertex ===> (h, k) (2, 4)

The parabola passes through the point: (x, y) ==> (3, 6)

Let's find the equation of a parabola.

To find the equation, use the general equation of a parabola with vertex (h, k):

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Where:

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(x, y) ==> (3, 6)

Substitute values into the general equation:

\begin{gathered} 6=a(3-2)^2+4 \\  \\ 6=a(1)^2+4 \\  \\ 6=a+4 \end{gathered}

Subtract 4 from both sides:

\begin{gathered} 6-4=a+4-4 \\  \\ 2=a \\  \\ a=2 \end{gathered}

Substitute 2 for a, and input the values of the vertex (h, k) in the general vertex equation:

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ANSWER:

y=2(x-2)^2+4

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