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2 years ago

Help me please!! My teacher never thought me this!

Mathematics

1 answer:

LenKa [72]2 years ago

4 0

Answer:

Step-by-step explanation:

.,n.m

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Help me... I did it again! I skipped the practice and study guides

Katyanochek1 [597]

Answer:

X = 1 3/4

Step-by-step explanation:

Hope this helps!

4 0

2 years ago

8x + 12 = 4r - 16 find r

Luda [366]

Answer:

r = 2x + 7

Step-by-step explanation:

get r on one side

8x + 12 + 16 = 4r

divide both sides by 4 to get r by itself

8x/4 + 12/4 + 16/4 = 4r/4

2x + 3 + 4 = r

2x + 7 = r

r = 2x + 7

8 0

2 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

Which expressions best represents the area of the rectangle

nikitadnepr [17]

Area of rectangle = length x width

(x + 12)(x - 5$

6 0

3 years ago

I need help with this anyone?

anastassius [24]

Answer:

c is the correct answer

7 0

2 years ago