All categories

3 years ago

A $260 suit price is marked down 10 % find the sale price

Mathematics

2 answers:

leva [86]3 years ago

7 0

Step-by-step explanation: We first need to find the discount.

The formula for discount is shown below.

Original Price × Rate of Discount = Discount

So here, the original price is $260 and the

rate of discount is 10% off which we can write as .10.

So we multiply 260 by .20

260 x .10 gives us 26.

So the discount is $26.

Now let's find the sale price.

The formula for sale price is shown below.

Original Price - Discount = Sale Price

Since the original price is $260 ad the discount is $26,

we have 260 - 26 which gives us 234.

So the sale price of the suit is $234.

NikAS [45]3 years ago

3 0

Answer:

260*0.90=sales price=234

Step-by-step explanation:

You might be interested in

Write an equation of the line through the given points (0, 4), (3, 3)

andre [41]

Hello! :)

Step-by-step explanation:

$Slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}$

$\frac{3-4}{3-0}=\frac{-1}{3}=-\frac{1}{3}$

Therefore, the slope is -1/3.

-1/3 is the final answer.

Hope this helps!

Have a nice day! :)

-Charlie

Thank you!

4 0

3 years ago

Which term describes a fraction that has a polynomial in its numerator and denominator?

pentagon [3]

Rational expression refers to a fraction in which the numerator and denominator are polynomials.

3 0

3 years ago

Read 2 more answers

And the number 6,497.4, the four next to the six is worth ___ times the other four.

FrozenT [24]

Yeah the answer is c

8 0

3 years ago

part 3. Find the value of the trig function indicated, use Pythagorean theorem to find the third side if you need it.

Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

$10)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{16}{20}\quad \rightarrow \large\boxed{\dfrac{4}{5}}$

Note: 12² + opposite² = 20² → opposite = 16

$11)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{\sqrt{11}}{6}\quad =\large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

5 0

3 years ago

Write the log equation as an exponential equation. You do not need to solve for x.

V125BC [204]

Answer:

(x-6)^3x-5 =6

Step-by-step explanation:

logb a=c ------> b^c =a

7 0

3 years ago