8 litres (amount of 20% solution needed) and 7 litres for (amount of 50% solution needed)
<u>Step-by-step explanation:</u>
Let consider ‘x’ for 20% acid solution and (15 – x) for 50% acid solution. And so, the equation would be as below,
20% in x + 50% in (15 – x) = 15 litres of 34%
Convert percentage values, we get
0.20(x) + 0.50 (15 – x) = 15 (0.34)
0.20 x + 7.5 – 0.50 x = 5.1
-0.3 x + 7.5 = 5.1
0.3 x = 7.5 – 5.1
0.3 x = 2.4
Apply ‘x = 8’ value in (15 – x) we get,
15 – 8 = 7 litres
The value of 7 litres for (amount of 50% solution needed)
1) The solution for m² - 5m - 14 = 0 are x=7 and x=-2.
2)The solution for b² - 4b + 4 = 0 is x=2.
<u>Step-by-step explanation</u>:
The general form of quadratic equation is ax²+bx+c = 0
where
- a is the coefficient of x².
- b is the coefficient of x.
- c is the constant term.
<u>To find the roots :</u>
- Sum of the roots = b
- Product of the roots = c
1) The given quadratic equation is m² - 5m - 14 = 0.
From the above equation, it can be determined that b = -5 and c = -14
The roots are -7 and 2.
- Sum of the roots = -7+2 = -5
- Product of the roots = -7
2 = -14
The solution is given by (x-7) (x+2) = 0.
Therefore, the solutions are x=7 and x= -2.
2) The given quadratic equation is b² - 4b + 4 = 0.
From the above equation, it can be determined that b = -4 and c = 4
The roots are -2 and -2.
- Sum of the roots = -2-2 = -4
- Product of the roots = -2-2 = 4
The solution is given by (x-2) (x-2) = 0.
Therefore, the solution is x=2.
Answer:
C the 90 degrees
Step-by-step explanation:
F(3)=2*3-8=-2.
Hope that helps.
Answer:
B. About 2% of the boys are eligible to be a small forward on the team
Step-by-step explanation:
Recall : 1 feets = 12 inches
Point guard = 6’2" – 6’6" tall = 74 - 78 inches
Mean = 70 ; Standard deviation = 4
Z = (x - mean) / standard
P(x < 74) = (74 - 70) / 4 = 1
P(x < 78) = (78 - 70) / 4 = 2
0.97725 - 0.84134 = 0.13591
Small forward : 6'6" = 78 inches
P(x ≥ 78) = (78 - 70) / 4 = 2
P(z ≥ 2) = 0.02275 = 2.275% about 2%
Centre : 6'8" = 80
P(x ≥ 80) = (80 - 70) / 4 = 2.5
P(z ≥ 2.5) = 0.0062097 = 0.62%
