The reaction equation is:
Li + Br → LiBr
39 grams of Li = 39 / 7 = 5.57 moles of lithium
41.5 grams of Br = 41.5 / 80 = 0.52 mole of bromine
Two naturally occurring isotopes of antimony are shown in the pic with their abundance
Convert 10g of NaOH to moles using the molar mass.
10 g NaOH / 39.997 g/mol NaOH = 0.25 mol NaOH
NaOH is a strong base so it dissolves completely in solution, so you’ll have 0.25 mol of OH-. Calculate the molarity of OH-.
0.25 mol OH / 0.250 L = 1.0 M OH-
Calculate the pOH. pOH = -log(1.0) = 0
pH = 14 - pOH = 14
Answer:
3.9
Explanation:
Let's consider the following reaction at equilibrium.
CO(g) + Cl₂(g) ↔ COCl₂(g)
We can find the pressures at equilibrium using an ICE chart.
CO(g) + Cl₂(g) ↔ COCl₂(g)
I 0.96 1.15 0
C -x -x +x
E 0.96-x 1.15-x x
The sum of the partial pressures is equal to the total pressure.
pCO + pCl₂ + pCOCl₂ = 1.47
(0.96-x) + (1.15-x) + x = 1.47
2.11 - x = 1.47
x = 0.64
The pressures at equilibrium are:
pCO = 0.96 - x = 0.32 atm
pCl₂ = 1.15 - x = 0.51 atm
pCOCl₂ = x = 0.64 atm
The pressure equilibrium constant (Kp) is:
Kp = pCOCl₂ / pCO × pCl₂
Kp = 0.64 / 0.32 × 0.51
Kp = 3.9