Answer : The boiling point of the resulting solution is, 
Explanation :
Formula used for Elevation in boiling point :
or,
where,
= boiling point of solution = ?
= boiling point of water = 
= boiling point constant = 
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
= mass of solute (sucrose) = 5.0 g
= mass of solvent (water) = 10.0 g
= molar mass of solute (sucrose) = 342.3 g/mol
Now put all the given values in the above formula, we get:
Therefore, the boiling point of the resulting solution is,
Moles KClO₃ = 0.239
<h3>Further explanation</h3>
Given
Reaction
2KClO₃(s) ⇒2KCl(s) + 3O₂(g)
P water = 23.8 mmHg
P tot = 758 mmHg
V = 9.07 L
T = 25 + 273 = 298 K
Required
moles of KClO₃
Solution
P tot = P O₂ + P water
P O₂ = P tot - P water
P O₂ = 758 - 23.8
P O₂ = 734.2 mmHg = 0.966 atm
moles O₂ :
n = PV/RT
n = 0.966 x 9.07 / 0.082 x 298
n = 0.358
From equation, mol ratio KClO₃ : O₂ = 2 : 3, so mol KClO₃ :
= 2/3 x mol O₂
= 2/3 x 0.358
= 0.239
Propes I think
Sorry if it’s wrong
