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Inessa [10]
2 years ago
15

A weather balloon has a volume of 200.0 L at a pressure of 760 mm Hg. As it rises, the pressure decreases to 282 mm Hg.

Chemistry
1 answer:
Bas_tet [7]2 years ago
7 0

Answer:

a. Increase

b. 539 L

Explanation:

Step 1: Given data

  • Initial volume (V₁): 200.0 L
  • Initial pressure (P₁): 760 mmHg
  • Final volume (V₂): ?
  • Final pressure (P₂): 282 mmHg

Step 2: Calculate the final volume of the gas

The pressure of the gas is inversely proportional to the volume. So, as the pressure decreases, the volume must increase. Assuming constant temperature and ideal behavior, we can calculate the final volume of the gas using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁/P₂

V₂ = 760 mmHg × 200.0 L/282 mmHg = 539 L

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ammonia gas is used as refrigerant 0.474 atm. Pressure is required to change 2000 cm3 sample of ammonia initially at 1.0 atm to
Andreas93 [3]

Answer: The pressure required is 0.474 atm

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}V}   (At constant temperature and number of moles)

The equation is,

{P_1V_1}={P_2V_2}

where,

P_1 = initial pressure of gas = 1.0 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 2000cm^3

V_2 = final volume of gas = 4.22dm^3=4220cm^3    (1dm^3=1000cm^3)

Now put all the given values in the above equation, we get:

{1.0\times 2000}={P_2\times 4200}

P_2=0.474atm

The pressure required is 0.474 atm

5 0
2 years ago
What is the role of the kinetic theory of matter in the process of solutes being dissolved into solvents?
hjlf

Answer:

i'd say the second choice.

Explanation:

the rise in temperature causes the particles to vibrate causing motion. they collide thus resulting to the weakening of the particles.

hope it is of use to you.

6 0
3 years ago
A 20.0g sample of metal with a specific heat of 5 J/(g°C) raised it's initial temperature to 40.0 when 500J heat was added. What
slavikrds [6]

The initial temperature of the metal = 35 °C

<h3>Further explanation</h3>

Heat can be formulated :

Q = m . c . ΔT

Q = heat, J

c = specific heat, J/g C

ΔT = temperature, °C

m = 20 g

c = 5 J/(g°C)

Q = 500 J

T₁ = 40 C

the initial temperature :

\tt \Delta t(T_2-T_1)=\dfrac{Q}{m.c}\\\\40-T_1=\dfrac{500}{20.5}\\\\40-T_1=5\\\\T_1=35^oC

3 0
2 years ago
Small children are occasionally injured when they try to inhale helium from a compressed helium tank. If a small child tries to
swat32

Answer:

26.0 moles

Explanation:

Given the formula;

PV =nRT

P= pressure of the gas

V = volume of the gas

n = number of moles of the gas

R = gas constant

T = temperature

n = PV/RT

n = 125 * 5/0.082 * (20 + 273)

n = 625/24.026

n = 26.0 moles

3 0
2 years ago
A chemist needs to create a series of standard Cu2+(aq) solutions for an absorbance experiment. For the first standard, he uses
morpeh [17]

Answer:

0.01 M

Explanation:

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First we must obtain the concentration of the solution in the 250ml flask from

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Where;

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C2 = concentration of the diluted solution

V2= volume of the diluted solution

2.61 × 10 = C2 × 250

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Hence for solution in 100ml flask;

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C2 = 0.1 × 10/100

C2 = 0.01 M

6 0
3 years ago
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