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kolbaska11 [484]
2 years ago
14

PLEASE HELP!

Chemistry
1 answer:
Tanzania [10]2 years ago
3 0
Molar mass:

KCl = 74.55 g/mol

KClO3 = 122. 55 g/mol

  <span>Calculation of the mass of KClO3 :</span>

<span>2 KClO3 =  2 KCl + 3 O2</span>

2* 122.55 g KClO3 ------------------ 2 * 74.55 g KCl
mass KClO3 ?? --------------------- 25.6 g KCl

mass KClO3 = 25.6 * 2 * 122.55 / 2 * 74.55

mass KClO3 = 6274.56 / 149.1

mass = 42.082 g of  KClO3

Therefore:

1 mole KClO3 ---------------------- 122.55 g
?? moles KClO3 ------------------- 42.082 g

moles KClO3 = 42.082 * 1 / 122.55

moles KClO3 = 42.082 / 122.55

=> 0.343 moles of KClO3


Answer C

hope this helps!

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Hello,

In this case, given the volume and concentration of lithium hydroxide and the volume of chloric acid, we can compute the concentration of the neutralized acid by using the following equation:

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<h3>Further explanation</h3>

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