13.5g
Explanation:
Given parameters:
Mass of Na = 10g
Mass of O₂ = 10g
Unknown:
Mass of products formed = ?
Balanced equation = ?
Solution:
The balanced chemical equation is shown below:
4Na + O₂ ⇒ 2Na₂O
In any reaction, the specie in short supply determines the extent of the reaction.
This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.
let us convert to moles;
Number of moles of Na = 
= 0.435mole
Number of moles of O₂ = 
= 0.313mole
From the given equation;
4 moles of Na requires 1 mole of O₂;
0.435 moles of Na will require 
= 0.11 moles
But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles
We see that Na is the limiting reagent;
4 moles of Na gives 2 mole of Na₂O
0.435 moles of Na will give 
= 0.22 moles
Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g
learn more:
Number of moles brainly.com/question/1841136
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Answer:
Explanation:
If the enzyme active site is complementary to the substrate conformation rather than to the transition state, it is unlikely that the reaction will proceed and release a product, because the enzyme-substrate complex will be tightly bound (ΔG will raise).
On the other hand, when the enzyme active site is complementary to the transition state, the substrate will not be tightly bound and will be more prone to be transformed into the product (<u>ΔG will be lowered</u>) and afterward, be released.
The weak interactions (non-covalent bonds) will stabilize the energy of the transition state and reduce its energy, thus lowering the activation energy). If the transition state is stable, it will form more easily and<u> the reaction will be more likely to proceed.</u>
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8.03 solutions report is described below.
Explanation:
8.03 Solutions Lab Report
In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.
Pre-lab Questions:
In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.
Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).
Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.
The correct answer is H2SO3 I took the assignment already
Answer:
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Explanation:
ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm.................... candyunicorns1999 has left the chat
