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Alinara [238K]
3 years ago
15

Does a rumor spread faster in a gym where all of

Chemistry
1 answer:
MArishka [77]3 years ago
4 0
No

Explanatory on

People are antsy to get back to their normal exercise routines, but many are left wondering how risky going to a gym is right now.
Researchers from South Korea recently warned people against rigorously exercising in confined spaces like fitness studios.
Moist, warm air combined with turbulent air flow from exercising may create an environment in which viru
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Equal molar amounts of H2 and I2 are placed into an evacuated container and heated to 445°C, where the following equilibrium is
Rus_ich [418]

<u>Answer:</u> The initial concentration of H_2\text{ and }I_2 are 0.0192 M and 0.0192 M respectively.

<u>Explanation:</u>

We are given:

Equilibrium concentration of HI = 0.030 M

Moles of hydrogen gas = Moles of iodine gas (concentration will also be the same)

For the given chemical equation:

                  H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>            x     x        -

<u>At eqllm:</u>     x-c    x-c     2c

Calculating the value of 'c'

2c=0.030\\\\c=\frac{0.030}{2}=0.015M

The expression of K_{eq} for above reaction follows:

K_{eq}=\frac{[HI]^2}{[H_2]\times [I_2]}

We are given:

K_{eq}=50.2

[H_2]=(x-c)=(x-0.015)

[I_2]=(x-c)=(x-0.015)

Putting values in above equation, we get:

50.2=\frac{(0.030)^2}{(x-0.015)\times (x-0.015)}\\\\x=0.0108,0.0192

Neglecting the value of x = 0.0108 M, because the initial concentration cannot be less than the equilibrium concentration.

x = 0.0192 M

Hence, the initial concentration of H_2\text{ and }I_2 are 0.0192 M and 0.0192 M respectively.

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Answer:

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C6H8 has the empirical formulae as <em>C3H4</em>

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Answer:

What do you need help with

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