x+y≤30 and 2.50x+2.75y≥44 are the inequalities that model given situation.
Step-by-step explanation:
Given,
Number of banana breads and nut breads to bake = at most 30
At most 30 means the amount cannot exceed 30.
Selling price of each banana bread = $2.50
Selling price of each nut bread = $2.75
Amount to make = $44 at least
At least 44 means that the amount cannot be less than 44.
Let,
x represent the number of loaves of banana bread to be sold
y represent the number of loaves of nut bread to be sold
x+y≤30
2.50x+2.75y≥44
x+y≤30 and 2.50x+2.75y≥44 are the inequalities that model given situation.
Keywords: linear inequalities, addition
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Since the question only asks for bagels, put the cream-cheese idea aside.
The total spent has to be less than $7 so an equation can be this: $0.75x<$7 where x is the number of bagels
All that is needed is a single counter-example.
One counter-example is to multiply the monomial x^3 with the binomial x^7-10x^4
We then get...
x^3*(x^7-10x^4) = x^3*x^7 + x^3*(-10x^4)
x^3*(x^7-10x^4) = x^10 - x^7
The result we get is a binomial as there are still only two terms here. We would need three terms to have a trinomial.
