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Juli2301 [7.4K]
3 years ago
6

In circle P with MLNRQ =60, find the mLNPQ

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
7 0
Answer is 120
AngNPQ=2*angNRQ=120
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(will give BRAINLIEST)The formula for the perimeter of a rectangle Is P = 2(1+w). Part A. Rewrite the formula for the perimeter
shepuryov [24]
A. W = P/2 - 1

B. First you need to divide both sides by 2 to get rid of the 2 on the side of the w. Then you need to take 1 away from both sides.

Whatever you do to one side, you must do to the other.
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4 0
3 years ago
A student solved this problem and said the answer is 5 pounds. Todd has two packages of hamburger. One package weighs pound and
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3 years ago
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Write the equation of the perpendicular bisector of . Point B is located at (–3, 1), and point C is located at (1, 5).
maxonik [38]

The equation of perpendicular bisector of BC is

y=-x+2

Further explanation:

A perpendicular bisector passes through the mid-point of a line so to get an ordered pair from which the perpendicular bisector will pass we need to find the mid-point of BC.

Mid-point = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )\\Here\\(x_1,y_1) = (-3,1)\\(x_2,y_2) = (1,5)\\Putting\ values\ in\ formula\\M = (\frac{-3+1}{2} , \frac{1+5}{2} )\\= (\frac{-2}{2} ,\frac{6}{2})\\= (-1, 3)

So the perpendicular bisector will pass through (-1,3)

Let m1 be the slope of BC

Then

m_1 = \frac{y_2-y_1}{x_2-x_1} \\=\frac{5-1}{1+3} \\=\frac{4}{4}\\ =1

Let m2 be the slope of perpendicular bisector

We know that the product of slopes of perpendicular lines is -1.

m_1.m_2 = -1\\1*m_2 = -1\\m_2 = -1

The standard form of point-slope form of line is:

y=mx+b

Putting the value of slope of bisector we get

y=(-1)(x)+b\\y=-x+b

To find the value of b, put the ordered pair (-1,3) in the equation

3 = -(-1) +b\\3= 1+b\\3-1 =b\\b=2\\

Putting the values of m and b in standard form

y=-x+2

Hence the equation of perpendicular bisector of BC is

y=-x+2

Keywords: Perpendicular bisector, Point-slope form

Learn more about point-slope form at:

  • brainly.com/question/7490805
  • brainly.com/question/8358304

#LearnwithBrainly

6 0
3 years ago
Pre-Calc help:
stepladder [879]

Answer:

8x^2+8y^2-79x-32y+95=0

Step-by-step explanation:

Let the equation be : x^2+y^2+2gx+2fy+c=0

The point (1,1) must satisfy this equation.

1^2+1^2+2g*1+2f*1+c=0\\2g+2f+c=-2---(1)

Similarly, the point (1,3) must satisfy:

1^2+3^2+2g*1+2f*3+c=0\\1+9+2g+6f+c=0\\2g+6f+c=-10---(2)

Also for the point (9,2), we have:

9^2+2^2+2g*9+2f*2+c=0\\81+4+18g+4f+c=0\\18g+4f+c=-85---(3)

Solving the equations (1), (2) and (3) simultaneously, we get:

g=-\frac{-79}{16},f=-2,c=\frac{95}{8}

We Substitute this values to get:

x^2+y^2+2(\frac{-79}{16})x+2(-2)y+\frac{95}{8}=0

x^2+y^2-(\frac{79}{8})x-4y+\frac{95}{8}=0

Multiply through by 8 to get:

8x^2+8y^2-79x-32y+95=0

8 0
3 years ago
A number is randomly selected from {15, 16, 17, 18, 19, 20}. A is represented by the event that the number picked is less than o
Tatiana [17]
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 the denonator is 6 because that is the number of numbers there are, and the numerator is 2 because there are 2 numbers less than or equal to 16. you can simplify
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3 years ago
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