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scZoUnD [109]
3 years ago
13

I need help, please​

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0
Has to be C. The other answers are wrong
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

C

Step-by-step explanation:

12^2 = 144, 9^2 = 81, and 15^2 = 225.

144 + 81 = 225, therefore a^2 + b^2 = c^2.

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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
PLEASE HELP!! Trevor is writing a paper that must be 50,000 words long. He had already written 23,210 words. Write an inequality
almond37 [142]

Answer:

50,000 ≤ 23,210 + 5x

x = Average number of words per week

Step-by-step explanation:

Start off with 50,000 because that's how many words the paper needs to have.

Use "≤" because Trevor needs to write at least 50,000 words. (He can write more).

Trevor already wrote 23,210 words plus x words per week for 5 weeks.

(Solving for x will help you find the average number of words Trevor must write per week for 5 weeks).

5 0
3 years ago
Kyle is pulled back on a swing so that the rope forms an angle of 30° with the vertical. The distance from the top of the swing
olga_2 [115]
This would be 12 - 12*cos(30) = 12 - 6\sqrt{3} =  1.608 ft off the ground. 
6 0
3 years ago
Which number from the set of numbers {3, 5, 6, 7} makes the equation below TRUE?
beks73 [17]

Answer:

6

Step-by-step explanation:

replace x with 6 in the ecuation.

4(6)=24 - 8 =16

5 0
3 years ago
Read 2 more answers
HELP ME PLS I NEED THIS !!!!
ZanzabumX [31]

Answer:

Go google the answer

Step-by-step explanation:

3 0
3 years ago
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