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Leona [35]
3 years ago
10

A game decreased in price by 1/4 after the reduction it was price at £36 what was the original price

Mathematics
1 answer:
amid [387]3 years ago
7 0
The original price was £48
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What is the area of this trapezoid?
pantera1 [17]

Answer:

Area=80 units squared

A=base*height

A=base*height/2

Step-by-step explanation:

7*8=56/2=28

7*8=56/2=28

3*8=24

28+28+24

56+24

80

5 0
3 years ago
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which of the following are the exact same distance from a parabola? A.Locus and Directix B.Axis and vertex C.Directix and Focus
Softa [21]

Answer:

C. Directrix and Focus

Step-by-step explanation:

Given choices are :

A. Locus and Directrix

B. Axis and vertex

C. Directrix and Focus or

D. Vertex and Locus

Now we need to find about which of the above choices are the exact same distance from a parabola.

By definition of parabola, vertex lies at equal distance from directrix and focus.

Hence choice  C. Directrix and Focus  is correct.

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3 years ago
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Triangle S and triangle L are scaled copies of one another,what is the scale factor from S to L
Naddika [18.5K]

The scale factor is 2

L = 2 * S

4 0
3 years ago
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The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an
solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable <em>X</em> can be defined as the pregnancy length in days.

Then, from the provided information X\sim N(\mu=268, \sigma^{2}=12^{2}).

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ <em>z</em> = 1.23

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ <em>z</em> = -1.645

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

8 0
3 years ago
A number increased by 6 is 13. What is the number?*
Oliga [24]

Answer:

7

Step-by-step explanation:

Simply subtract 6 from 13.

13-6=7

Hope this helps! :)

4 0
3 years ago
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