2 years ago

Please solve I need help pls

Mathematics

1 answer:

Ad libitum [116K]2 years ago

7 0

The answer is adjacent, 69° and 112°.

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T (2,10) is the midpoint of CD. The coordinates of D are (2,13). What are the coordinates of C?

Sati [7]

Your answer should be D because 13-10=3 and 10-3=7 (2, 7)!

7 0

3 years ago

Question is attached could you please help me and explain how you got your answer?

vampirchik [111]

Okay so combine like terms
10x-4x= 6x
2-8= -6

6x=-6
x= -1

Now to check:
10(-1)-2=4(-1)-8
-10-2=-4-8
-12=-12

3 0

3 years ago

Read 2 more answers

The assessed value of a certain house is Rs.15 000. If the the relevant council institutions charges 5℅ of the value of the hous

bezimeni [28]

Answer:

15000×5/100=100/100x

150×5=x

750=x

Assessed value that you have to pay for a year is Rs.750.00

Step-by-step explanation:

Have a great day!

4 0

2 years ago

I need helpppp !!! :((

Andrew [12]

Im not 100% sure but I do think it is Ratio (red to blue) of the areas

Step-by-step explanation:

3 0

3 years ago

Geometric Series assistance

Levart [38]

we have been asked to find the sum of the series

$\sum _{n=1}^5\left(\frac{1}{3}\right)^{n-1}$

As we know that a geometric series has a constant ratio "r" and it is defined as

$r=\frac{a_{n+1}}{a_n}=\frac{\left(\frac{1}{3}\right)^{\left(n+1\right)-1}}{\left(\frac{1}{3}\right)^{n-1}}=\frac{1}{3}$

The first term of the series is $a_1=\left(\frac{1}{3}\right)^{1-1}=1$

Geometric series sum formula is

$S_n=a_1\frac{1-r^n}{1-r}$

Plugin the values we get

$S_5=1\cdot \frac{1-\left(\frac{1}{3}\right)^5}{1-\frac{1}{3}}$

On simplification we get

$S_5=\frac{121}{81}$

Hence the sum of the given series is $\frac{121}{81}$

5 0

2 years ago