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ValentinkaMS [17]
3 years ago
8

Convert 23/5into a mixed number.

Mathematics
2 answers:
Vitek1552 [10]3 years ago
6 0

Answer:

the answer is 4 3/5

Step-by-step explanation:

8090 [49]3 years ago
3 0

Answer:

4 3/5

Step-by-step explanation:

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Hatshy [7]
That is a hyperbola that is slanted

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I need help ASAP...<br><br> (reward 10 points)
marta [7]

Answer:

it may be C im sorry if its wrong

Step-by-step explanation:

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6 0
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Y/x^2 + y/x^3<br><br>perform the operation and express your answer as a single fraction​
umka2103 [35]

Answer:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

Step-by-step explanation:

Given the expression

\frac{y}{x^2}+\frac{y}{x^3}

Let us perform the operation and express your answer as a single fraction​

\frac{y}{x^2}+\frac{y}{x^3}=\frac{x^3y+x^2y}{x^5}

            =\:\frac{x^2\left(xy+y\right)}{x^5}

            =\frac{\left(xy+y\right)}{x^3}

Therefore, we conclude that:

\frac{y}{x^2}+\frac{y}{x^3}=\frac{yx+y}{x^3}

3 0
3 years ago
Find the center of mass of the wire that lies along the curve r and has density =4(1 sin4tcos4t)
dolphi86 [110]

The mass of the wire is found to be 40π√2 units.

<h3>How to find the mass?</h3>

To calculate the mass of the wire which runs along the curve r ( t ) with the density function δ=5.

The general formula is,

Mass = \int_a^b \delta\left|r^{\prime}(t)\right| d t

To find, we must differentiate this same given curve r ( t ) with respect to t to estimate |r'(t)|.

The given integration limits in this case are a = 0, b = 2π.

Now, as per the question;

The equation of the curve is given as;

r(t) = (4cost)i + (4sint)j + 4tk

Now, differentiate this same given curve r ( t ) with respect to t.

\begin{aligned}\left|r^{\prime}(t)\right| &=\sqrt{(-4 \sin t)^2+(4 \cos t)^2+4^2} \\&=\sqrt{16 \sin ^2 t+16 \cos ^2 t+16} \\&=\sqrt{16\left(\sin t^2+\cos ^2 t\right)+16}\end{aligned}

Further simplifying;

\begin{aligned}&=\sqrt{16(1)+16} \\&=\sqrt{16+16} \\&=\sqrt{32} \\\left|r^{\prime}(t)\right| &=4 \sqrt{2}\end{aligned}

Now, use integration to find the mass of the wire;

       \begin{aligned}&=\int_a^b \delta\left|r^{\prime}(t)\right| d t \\&=\int_0^{2 \pi} 54 \sqrt{2} d t \\&=20 \sqrt{2} \int_0^{2 \pi} d t \\&=20 \sqrt{2}[t]_0^{2 \pi} \\&=20 \sqrt{2}[2 \pi-0] \\&=40 \pi \sqrt{2}\end{aligned}

Therefore, the mass of the wire is estimated as 40π√2 units.

To know more about density function, here

brainly.com/question/27846146

#SPJ4

The complete question is-

Find the mass of the wire that lies along the curve r and has density δ.

r(t) = (4cost)i + (4sint)j + 4tk, 0≤t≤2π; δ=5

5 0
1 year ago
0.4 times 2.72=<br> I don’t know how I’m getting it wrong
gayaneshka [121]

Answer:

1.088 is the answer to the question

3 0
4 years ago
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