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2 years ago

What is the solution of 15+x=-2

Mathematics

2 answers:

anzhelika [568]2 years ago

7 0

Answer:

x=-17

Step-by-step explanation:

15+x=-2

Subtract 15 from both sides

15+x=-2

-15 -15

---------------

x=-17

kari74 [83]2 years ago

3 0

Answer:

x = -17

Step-by-step explanation:

We need to subtract 15 from both sides (so that x can be by itself) and when we do so we get x = -2 - 15 = -17.

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Express 148.502 in standard form Pls as soon as possible

LenKa [72]

Answer:

1.48502 × 10²

Step-by-step explanation:

A number expressed in standard form is

a × $10^{n}$ ( 1 ≤ a < 10 and n is an integer )

Given

148.502 ← express as a number between 1 and 10

1.48502

To obtain the original number we require to multiply by 100 , that is 10²

Thus

148.502 = 1.48502 × 10²

8 0

2 years ago

Read 2 more answers

Let w(s,t)=f(u(s,t),v(s,t)) where u(1,0)=−6,∂u∂s(1,0)=5,∂u∂1(1,0)=7 v(1,0)=−8,∂v∂s(1,0)=−8,∂v∂t(1,0)=6 ∂f∂u(−6,−8)=−1,∂f∂v(−6,−8

Blababa [14]

$w(s,t)=f(u(s,t),v(s,t))$

From the given set of conditions, it's likely that you are asked to find the values of $\dfrac{\partial w}{\partial s}$ and $\dfrac{\partial w}{\partial t}$ at the point $(s,t)=(1,0)$ .

By the chain rule, the partial derivative with respect to $s$ is

$\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}$

and so at the point $(1,0)$ , we have

$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial s}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=(-1)(5)+(2)(-8)=-21$

Similarly, the partial derivative with respect to $t$ would be found via

$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}$
$\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=(-1)(7)+(2)(6)=5$

6 0

3 years ago

1,367.5897 to the nearest whole

Inga [223]

Answer:

1368

hope this helps

have a good day :)

Step-by-step explanation:

6 0

3 years ago

Can someone please help me with this similar area question? I have the answer but I’m not sure how to get to it. Will make brain

Mumz [18]

Step-by-step explanation:

well there is a very simple point that you have mistaken tho:

484cm², 25cm²

Areas are defined in square cm but the radius is in cm

so:

$\sqrt{ \frac{484 {cm}^{2} }{25 {cm}^{2} } } = \frac{7.92}{r} = = = > 4.4 = \frac{7.92cm}{x} = = > x = \frac{7.92cm}{4.4} = x = 1.8cm$

and there you go

5 0

1 year ago

|x-8|<13 What is the solution

maks197457 [2]

Answer:

x = (-5, 21)

Step-by-step explanation:

|x - 8| < 13

1 .

x - 8 < 13
x < 8 + 13
x < 21

x - 8 > -13
x > 8 - 13
x > -5

Combined answer

-5 < x < 21
x = (-5, 21)

5 0

2 years ago