Answer:
B. 21.2
Step-by-step explanation:
Perimeter of ∆ABC = AB + BC + AC
A(-4, 1)
B(-2, 3)
C(3, -4)
✔️Distance between A(-4, 1) and B(-2, 3):




AB = 4 units
✔️Distance between B(-2, 3) and C(3, -4):




BC = 8.6 units (nearest tenth)
✔️Distance between A(-4, 1) and C(3, -4):




AC = 8.6 units (nearest tenth)
Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units
Inside, Lighthouse, Overboard (If You Can go Diagonal) Outback, Outdoors
Hope that helps :)
Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?
step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3
step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15
the answer Part 1) isy=(1/3)*x+15Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line
y=(1/3)*x+15then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
<span>the point does not belong to the given line
</span>
the answer Part 2) isthe point does not belong to the given line
see the attached figure