Does it have any ANSWER CHOISES!
Answer:
Step-by-step explanation:
Hello, first, let's use the product rule.
Derivative of uv is u'v + u v', so it gives:

Now, we distribute the expression of f(x) and find the derivative afterwards.

Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Answer:
Neither even nor odd.
Step-by-step explanation:
f(x) = 2(x + 1)^3 = 2x^3 + 18x^2 + 54x + 54
f(-x) = -2x^3 + 18x^2 - 54x + 54
If it was even f(x) would be = f(-x) so it is NOT EVEN.
-f(x) = 2x^3 - 18x^2 + 54x - 54
So f(-x) is not = -f(x) so it is not ODD either.