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Liula [17]
2 years ago
13

Consider the following statement:

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
8 0

Answer:

"All right, isoceles triangles are special right triangles."

yes it agree this statement. as in right isosceles triangle always two angles are 45 and remaining 90.

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Find the midpoint between the two points:<br> (2,3), (4,1)
grin007 [14]

Answer:

(3, 2 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

here (x₁, y₁ ) = (2, 3 ) and (x₂, y₂ ) = (4, 1 ) , then

midpoint = ( \frac{2+4}{2} , \frac{3+1}{2} ) = ( \frac{6}{2} , \frac{4}{2} ) = (3, 2 )

4 0
1 year ago
PLEASE HELP ME ALSO LOOK
saul85 [17]

Answer:

B. 0.73

Step-by-step explanation:

Add all numers so the first is 2/10 = 0.2

then 35/100 = 0.35

and then 16/100 = 0.16

finally 2/100 = 0.02

Now add all decimals which is equal to 73/100 = 0.73 and that's your answer.

^Virtuoso^

8 0
3 years ago
Can y = sin(t2) be a solution on an interval containing t = 0 of an equation y + p(t) y + q(t) y = 0 with continuous coefficient
JulsSmile [24]

Answer:

Step-by-step explanation:

y = sin(t^2)

y' = 2tcos(t^2)

y'' = 2cos(t^2) - 4t^2sin(t^2)

so the equation become

2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0

when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.

7 0
2 years ago
In April 2011, an online social networking site had approximately 200 million registered accounts. In August, the number of regi
fenix001 [56]
All you have to do is move your decimal point over eight places to the right and then subtract that from the first number and you have your answer. 
6 0
3 years ago
What is the greatest common factor of the terms in the expression 21x-18x+28xy
xeze [42]

Answer:

x(3+28y)

Step-by-step explanation:

21x-18x+28xy

3x+28xy

x(3+28y)

8 0
2 years ago
Read 2 more answers
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