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3 years ago

Help me please i do not understand

Mathematics

1 answer:

Andre45 [30]3 years ago

3 0

Answer:

the equation of the line is:

y=-2x+-3

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Find n(A) for the set.

charle [14.2K]

Answer:

b.n(A)=1800

Step-by-step explanation:

b.n(A)=1800

5 0

2 years ago

Mr. Chen filled a wading pool with 20 gallons of water. How many pints of water did he put in a pool

eduard

Answer:

160 pints

Step-by-step explanation:

Every 1 gallon = 8 pints.

20x8=160

8 0

3 years ago

Read 2 more answers

Drag tiles to describe each fraction Tiles may be used once, more than once, or not at all.

jonny [76]

Answer:

1/3 is less than 2/3

7/9 is greater than 2/3

4/10 is less than 2/3

4/6 is equal to 2/3

5 0

3 years ago

According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, 62% of graduate

Romashka-Z-Leto [24]

Answer:

C. 30

Step-by-step explanation:

-It is a statistical rule of thumb that the size of a sample must be $n\geq 30$ .

-This size is deemed adequate for the Central Limit Theorem to hold.

-At this size or greater, the shape of the resultant distribution is normal.

#It should however be noted, that for a normal distribution the CLT holds even for smaller sample sizes.

5 0

3 years ago

An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2 : Suppose a sample of

rewona [7]

Answer:

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.

333 - 257 = 76 have spills.

This means that $n = 333, \pi = \frac{76}{333} = 0.228$

80% confidence level

So $\alpha = 0.2$ , z is the value of Z that has a pvalue of $1 - \frac{0.2}{2} = 0.9$ , so $Z = 1.28$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 - 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.199$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 + 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.257$

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

6 0

3 years ago