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Katarina [22]
3 years ago
13

How many solutions does this linear system of equations have?

Mathematics
2 answers:
Mazyrski [523]3 years ago
8 0
It has infinite solutions
Irina18 [472]3 years ago
4 0
It has infinite solutions
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What is the rule in this sequence (0,21) (1,18) (2,15) (3,12) (4,9) (5,6) (6,3) (7,0) (8,-3) (9,-6) (10,-9)
anastassius [24]

Answer:

x + 1 & y - 3

Step-by-step explanation:

Because... the x-values are going up by 1 digit each and the y-values are going down by 3 digits each.

6 0
3 years ago
When simplified, the expression shown below can be written as which choice shown?
DanielleElmas [232]
(3) -34 is your answer
8 0
3 years ago
In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?
ycow [4]

Answer:

<em>Cathy was born in 1980 and she was 18 years old in 1998</em>

Step-by-step explanation:

<u>Equations</u>

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

x=1000a+100b+10c+d

In 1998, Cathy's age was

1998-(1000a+100b+10c+d)

And it must be equal to the sum of the four digits

1998-(1000a+100b+10c+d)=a+b+c+d

Rearranging

1998=1001a+101b+11c+2d

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

1998=1001+909+11c+2d

Operating

88=11c+2d

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0
3 years ago
Felipe Rivera's savings account has a balance of 2163 After 3 years what will the amount of interest be at 4%
Allisa [31]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad  \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$2163\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &3 \end{cases} \\\\\\ A=2163\left(1+\frac{0.04}{4}\right)^{4\cdot 3}\implies A=2163(1.01)^{12}\implies A\approx 2437.322540175

3 0
3 years ago
Equations
Flauer [41]

Answer:

Step-by-step explanation:

-3x + 4y = -18

8x - 4y =   28

5x = 10

x = 2

4 - y = 7

-y = 3

y = -3

(2, -3)

8 0
3 years ago
Read 2 more answers
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