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myrzilka [38]
3 years ago
5

'Do you believe the quarantine crisis will leave no scars'?'.... , I believe we

Mathematics
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

B .on the contrary...........

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Problem: It takes Chantal 6 hours to plow a garden. When her Grandpa Joss comes to visit, it takes him 10 hours to do the same a
Sidana [21]

Answer:

it would take 7 minutes to plow the whole garden.

Step-by-step explanation:

3 0
2 years ago
PLEASE HELP ASAP &lt;333<br><br> What is the sum of the geometric series ?
ankoles [38]

Answer:

Step-by-step explanation:

There are a couple of ways to do this. You could figure all four terms out and add them, which is likely the simplest way.

One:     6^(1 - 1) = 6^0 =      1

Two:     6^(2 - 1) = 6^1 =      6

Three:   6^(3 - 1) = 6^2 =   36

Four:     6^(4 - 1) = 6^3 =   216

Sum = 259

7 0
4 years ago
Two of the angles in a triangle measure 15° and 27°. What is the measure of the third angle?
VashaNatasha [74]

Answer:

103

Step-by-step explanation:

6 0
3 years ago
A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a
zavuch27 [327]

Answer:

Area = 3\dfrac{15}{16}\ sq\ ft

Area is greater than 3\frac{1}{2} sq ft.

Step-by-step explanation:

Length of rectangular sign board = 3\frac{1}{2} ft

Width of rectangular sign board = 1\frac{1}{8} ft

Area of a rectangle is given by the formula:

A = Length \times Width

To find the area, we are going to multiply 3\frac{1}{2} with 1\frac{1}{8}.

1\frac{1}{8} is greater than 1.

Therefore the multiplication will be greater than 3\frac{1}{2}.

Hence, we can say that area will be greater than 3\frac{1}{2} sq ft.

Area of the sign:

A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft

8 0
3 years ago
Pls help me solve the question I Need to finish quickly
Effectus [21]
45: 100% - 17% = 83%

47: 44/2 = 22 
      22 - 1 = 21

See attached file

4 0
3 years ago
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