Answer:
D
Step-by-step explanation:
Put m+2 in place of 'x'
(m+2)^2 + 1 <======expand
m^2 + 4m + 4 + 1 =
m^2 + 4m + 5
Answer:
Step-by-step explanation:
- -13x < 65
- x > - 65/13
- x > -5
- x = (-5, + oo)
Answer:
Step-by-step explanation:
No but if you copy and paste the question to me i can get you the answers :)
Answer:
digits are: 0, 4, 8. The required number is: 480.
Step-by-step explanation:
→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.
→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.
→ After evaluation this equation, x=0 - this is ones digit;
→ x+4=0+4=4 - this is hundreds digit;
→ 2(x+4)=2(0+4)=8 - this is ten digit.
For a two-tailed test we need to halve 0.01, giving 0.005. Then we need to sutract 0.005 from 0.5, giving 0.5 - 0.005 = 0.495. Looking up the p value of 0.495 in an inverse normal probability table we obtain the value z = 2.5758. Therefore the critical values are -2.5758 and 2.5758.