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evablogger [386]
3 years ago
11

Which function produces an output of 5 for an input of -6?

Mathematics
1 answer:
kodGreya [7K]3 years ago
3 0

Answer:

The answer is D

Step-by-step explanation:

Since the input is -6, you input it into the equation. That would make it f(-6)=-(-6)-1 which would be equivalent to f(-6)=6-1 , as the negatives at the beginning of the equation cancel each other out and make it positive. Then you solve and get 5, which is your output. Hope I could help :)

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Solve equation 3k+45=8k+25
Brrunno [24]

Answer:

k=4

Step-by-step explanation:

First, we can subtract 3k on both sides. It is ultimately easier to start by subtracting the term with a variable. This would result in 45=5k+25. Then, we can subtract 25 on both sides to get closer to isolating k. This becomes 20=5k. We can then divide by 5 on both sides. This means that k=4.

5 0
3 years ago
Read 2 more answers
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frutty [35]

Answer:

15

Step-by-step explanation:

Hi there! :)

If you created 5 circles cut into thirds, you would create 15 1/3 pieces.

You can also use the KCF method to solve this!

7 0
3 years ago
Subtract<br> 505,000 - 427,619 -
yawa3891 [41]

Answer:

77381 is your answer

Step-by-step explanation:

5 0
3 years ago
The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900
Tems11 [23]
The poopulation exponential model is given by

P(t)=P_0e^{kt}

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

970=790e^{50k} \\  \\ \Rightarrow e^{50k}=1.228 \\  \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\  \\ \Rightarrow k=0.0041

Thus, the exponential equation using the 1750 and the 1800 population values is P(t)=790e^{0.0041t}

The population of 1900 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times150} \\  \\ =790e^{0.6158}=790(1.8511) \\  \\ =1,462

The population of 1950 using the 1750 and the 1800 population values is given by

P(t)=790e^{0.041\times200} \\  \\ =790e^{0.821}=790(2.2729) \\  \\ =1,796

From the table, it can be seen that the actual figure is greater than the exponential model values.
7 0
3 years ago
Help me find the rate of change for these points listed here, and also write an equation:
valentinak56 [21]
54-2/0-3=-17,3=a
Y=-17,3x+54 b=54 because its the initial value of y when x =0
When x=1 y=36,7
When x=2 y=19,4
I juste replaced 1 in the equation and did the calculation with my calculator
4 0
3 years ago
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