Given:
The equation is:
It cuts the x-axis and y- axis at the point A and B respectively.
The area of ∆AOB =12 sq.units.
To find:
The value of <em>k</em>.
Solution:
We have,
Substituting 
to find the y-intercept.
Substituting 
to find the x-intercept.
Area of a triangle is:
The height of the ∆AOB is 
because distance cannot be negative and the base of the ∆AOB is 
. So, the area of the ∆AOB is:
It is given that, the area of ∆AOB = 12 sq.units.
Therefore, the value of k is either 24 or -24.
Answer:
I think the answer for x is 1
Answer:
________________________________
write the equation
________________________________
multiply both numerator and denominator by √3+√2
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after multiplying numerator with √3+√2 we get→√3+√2
after multiplying denominator we get 3-2
________________________________
after subtracting 3 with 2 we get →1
________________________________
hence denominater is rationalized✓
hope it helped you:)
X^2 + x - 2 + 2x - 4....combine like terms
x^2 + 3x - 6 <=
Answer:
F(X) > 0 over the interval (-infinity, -4)
Step-by-step explanation:
F(x) is the function and really can be written like y. As you can see from the graph, between -4 and -infinity the graph is constantly increasing and will never decrease below zero again, therefore D (the 4th statement) is the correct one.
